Superquadratic sensitivity separation: recursive one #
This file proves the recurrences for the profiles of the next-level family at output true. At an
accepted input some row clause holds, and only flips inside its r target children or its o
labeled gate children (one per out-neighbour) can make the next-level predicate reject. Counting the
sensitive coordinates of these children bounds the side profile by
o * sideSensitivity F false + r * sideSensitivity F true, and the joint profile by the same
expression with jointSensitivity F false in place of sideSensitivity F false.
Main results #
recursive_sensitivity_one_at: pointwise sensitivity bound at an accepted input.recursive_side_one: the side profile of the next-level family attrueis at mosto * sideSensitivity F false + r * sideSensitivity F true.recursive_joint_one_at: pointwise joint sensitivity bound at an input accepted at two indices.recursive_joint_one: for nestedF, the joint profile of the next-level family attrueis at mosto * jointSensitivity F false + r * sideSensitivity F true.
References #
If every vertex of T has outdegree o and the next-level predicate at index q accepts x,
then its sensitivity at x is at most o * sideSensitivity F false + r * sideSensitivity F true.
If every vertex of T has outdegree o, then the side profile of the next-level family at
true is at most o * sideSensitivity F false + r * sideSensitivity F true.
Let F be nested and every vertex of T have outdegree o. If q < q' and the next-level
predicates at q and q' both accept x, then their joint sensitivity at x is at most
o * jointSensitivity F false + r * sideSensitivity F true.
If F is nested and every vertex of T has outdegree o, then the joint profile of the
next-level family at true is at most o * jointSensitivity F false + r * sideSensitivity F true.